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Python Institute PCEP - Certified Entry-Level Python Programmer Sample Questions (Q11-Q16):

NEW QUESTION # 11
A set of rules which defines the ways in which words can be coupled in sentences is called:

Answer: D

Explanation:
Syntax is the branch of linguistics that studies the structure and rules of sentences in natural languages. Lexis is the vocabulary of a language. Semantics is the study of meaning in language. A dictionary is a collection of words and their definitions, synonyms, pronunciations, etc.
Reference: [Python Institute - Entry-Level Python Programmer Certification]


NEW QUESTION # 12
Assuming that the phone_dir dictionary contains name:number pairs, arrange the code boxes to create a valid line of code which adds Oliver Twist's phone number (5551122333) to the directory.

Answer:

Explanation:
phone_dir["Oliver Twist"] = ["5551122333"]
Explanation:

To correctly add Oliver Twist's phone number to the phone_dir dictionary, the code must follow this phone_dir["Oliver Twist"] = ["5551122333"] Now, let's match that with your code boxes and arrange them:
* phone_dir
* [
* "Oliver Twist"
* ]
* =
* [
* "5551122333"
* ]
Final Order:phone_dir # [ # "Oliver Twist" # ] # = # [ # "5551122333" # ]


NEW QUESTION # 13
What is the expected result of running the following code?

Answer: D

Explanation:
Explanation
The code snippet that you have sent is trying to use the index method to find the position of a value in a list.
The code is as follows:
the_list = [1, 2, 3, 4, 5] print(the_list.index(6))
The code starts with creating a list called "the_list" that contains the numbers 1, 2, 3, 4, and 5. Then, it tries to print the result of calling the index method on the list with the argument 6. The index method is used to return the first occurrence of a value in a list. For example, the_list.index(1) returns 0, because 1 is the first value in the list.
However, the code has a problem. The problem is that the value 6 is not present in the list, so the index method cannot find it. This will cause a ValueError exception, which is an error that occurs when a function or operation receives an argument that has the right type but an inappropriate value. The code does not handle the exception, and therefore it will terminate with an error message.
The expected result of the code is an unhandled exception, because the code tries to find a value that does not exist in the list. Therefore, the correct answer is C. The code raises an unhandled exception.


NEW QUESTION # 14
What is the expected output of the following code?

Answer: D

Explanation:
Explanation
The code snippet that you have sent is a conditional statement that checks if a variable "counter" is less than 0, greater than or equal to 42, or neither. The code is as follows:
if counter < 0: print("") elif counter >= 42: print("") else: print("") The code starts with checking if the value of "counter" is less than 0. If yes, it prints a single asterisk () to the screen and exits the statement. If no, it checks if the value of "counter" is greater than or equal to 42. If yes, it prints three asterisks () to the screen and exits the statement. If no, it prints two asterisks () to the screen and exits the statement.
The expected output of the code depends on the value of "counter". If the value of "counter" is 10, as shown in the image, the code will print two asterisks (**) to the screen, because 10 is neither less than 0 nor greater than or equal to 42. Therefore, the correct answer is C. * *


NEW QUESTION # 15
What is the expected result of the following code?

Answer: C

Explanation:
The code snippet that you have sent is trying to use the global keyword to access and modify a global variable inside a function. The code is as follows:
speed = 10 def velocity(): global speed speed = speed + 10 return speed print(velocity()) The code starts with creating a global variable called "speed" and assigning it the value 10. A global variable is a variable that is defined outside any function and can be accessed by any part of the code. Then, the code defines a function called "velocity" that takes no parameters and returns the value of "speed" after adding 10 to it. Inside the function, the code uses the global keyword to declare that it wants to use the global variable
"speed", not a local one. A local variable is a variable that is defined inside a function and can only be accessed by that function. The global keyword allows the function to modify the global variable, not just read it. Then, the code adds 10 to the value of "speed" and returns it. Finally, the code calls the function "velocity" and prints the result.
However, the code has a problem. The problem is that the code uses the global keyword inside the function, but not outside. The global keyword is only needed when you want to modify a global variable inside a function, not when you want to create or access it outside a function. If you use the global keyword outside a function, you will get a SyntaxError exception, which is an error that occurs when the code does not follow the rules of the Python language. The code does not handle the exception, and therefore it will terminate with an error message.
The expected result of the code is an unhandled exception, because the code uses the global keyword incorrectly. Therefore, the correct answer is A. The code is erroneous and cannot be run.
Reference: Python Global Keyword - W3SchoolsPython Exceptions: An Introduction - Real Python The code is erroneous because it is trying to call the "velocity" function without passing any parameter, which will raise a TypeError exception. The "velocity" function requires one parameter "x", which is used to calculate the return value of "speed" multiplied by "x". If no parameter is passed, the function will not know what value to use for "x".
The code is also erroneous because it is trying to use the "new_speed" variable before it is defined. The
"new_speed" variable is assigned the value of 20 after the first function call, but it is used as a parameter for the second function call, which will raise a NameError exception. The variable should be defined before it is used in any expression or function call.
Therefore, the code will not run and will not produce any output.
The correct way to write the code would be:
# Define the speed variable
speed = 10
# Define the velocity function
def velocity(x):
return speed * x
# Define the new_speed variable
new_speed = 20
# Call the velocity function with new_speed as a parameter
print(velocity(new_speed))
Copy
This code will print 200, which is the result of 10 multiplied by 20.
References:
[Python Programmer Certification (PCPP) - Level 1]
[Python Programmer Certification (PCPP) - Level 2]
[Python Programmer Certification (PCPP) - Level 3]
[Python: Built-in Exceptions]
[Python: Defining Functions]
[Python: More on Variables and Printing]


NEW QUESTION # 16
......

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